Integrand size = 22, antiderivative size = 56 \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=-\frac {49}{1215 (2+3 x)^5}+\frac {259}{486 (2+3 x)^4}-\frac {503}{243 (2+3 x)^3}+\frac {370}{243 (2+3 x)^2}-\frac {100}{243 (2+3 x)} \]
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Time = 0.02 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {90} \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=-\frac {100}{243 (3 x+2)}+\frac {370}{243 (3 x+2)^2}-\frac {503}{243 (3 x+2)^3}+\frac {259}{486 (3 x+2)^4}-\frac {49}{1215 (3 x+2)^5} \]
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Rule 90
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {49}{81 (2+3 x)^6}-\frac {518}{81 (2+3 x)^5}+\frac {503}{27 (2+3 x)^4}-\frac {740}{81 (2+3 x)^3}+\frac {100}{81 (2+3 x)^2}\right ) \, dx \\ & = -\frac {49}{1215 (2+3 x)^5}+\frac {259}{486 (2+3 x)^4}-\frac {503}{243 (2+3 x)^3}+\frac {370}{243 (2+3 x)^2}-\frac {100}{243 (2+3 x)} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.55 \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=-\frac {4028+19275 x+61470 x^2+116100 x^3+81000 x^4}{2430 (2+3 x)^5} \]
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Time = 2.29 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.52
method | result | size |
norman | \(\frac {-\frac {100}{3} x^{4}-\frac {430}{9} x^{3}-\frac {683}{27} x^{2}-\frac {1285}{162} x -\frac {2014}{1215}}{\left (2+3 x \right )^{5}}\) | \(29\) |
gosper | \(-\frac {81000 x^{4}+116100 x^{3}+61470 x^{2}+19275 x +4028}{2430 \left (2+3 x \right )^{5}}\) | \(30\) |
risch | \(\frac {-\frac {100}{3} x^{4}-\frac {430}{9} x^{3}-\frac {683}{27} x^{2}-\frac {1285}{162} x -\frac {2014}{1215}}{\left (2+3 x \right )^{5}}\) | \(30\) |
parallelrisch | \(\frac {6042 x^{5}+4140 x^{4}+3920 x^{3}+5760 x^{2}+2160 x}{480 \left (2+3 x \right )^{5}}\) | \(34\) |
default | \(-\frac {49}{1215 \left (2+3 x \right )^{5}}+\frac {259}{486 \left (2+3 x \right )^{4}}-\frac {503}{243 \left (2+3 x \right )^{3}}+\frac {370}{243 \left (2+3 x \right )^{2}}-\frac {100}{243 \left (2+3 x \right )}\) | \(47\) |
meijerg | \(\frac {9 x \left (\frac {81}{16} x^{4}+\frac {135}{8} x^{3}+\frac {45}{2} x^{2}+15 x +5\right )}{320 \left (1+\frac {3 x}{2}\right )^{5}}-\frac {3 x^{2} \left (\frac {27}{8} x^{3}+\frac {45}{4} x^{2}+15 x +10\right )}{640 \left (1+\frac {3 x}{2}\right )^{5}}-\frac {59 x^{3} \left (\frac {9}{4} x^{2}+\frac {15}{2} x +10\right )}{1920 \left (1+\frac {3 x}{2}\right )^{5}}+\frac {x^{4} \left (\frac {3 x}{2}+5\right )}{64 \left (1+\frac {3 x}{2}\right )^{5}}+\frac {5 x^{5}}{16 \left (1+\frac {3 x}{2}\right )^{5}}\) | \(110\) |
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Time = 0.22 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.88 \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=-\frac {81000 \, x^{4} + 116100 \, x^{3} + 61470 \, x^{2} + 19275 \, x + 4028}{2430 \, {\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )}} \]
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Time = 0.07 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.82 \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=\frac {- 81000 x^{4} - 116100 x^{3} - 61470 x^{2} - 19275 x - 4028}{590490 x^{5} + 1968300 x^{4} + 2624400 x^{3} + 1749600 x^{2} + 583200 x + 77760} \]
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Time = 0.21 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.88 \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=-\frac {81000 \, x^{4} + 116100 \, x^{3} + 61470 \, x^{2} + 19275 \, x + 4028}{2430 \, {\left (243 \, x^{5} + 810 \, x^{4} + 1080 \, x^{3} + 720 \, x^{2} + 240 \, x + 32\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.52 \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=-\frac {81000 \, x^{4} + 116100 \, x^{3} + 61470 \, x^{2} + 19275 \, x + 4028}{2430 \, {\left (3 \, x + 2\right )}^{5}} \]
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Time = 1.17 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.82 \[ \int \frac {(1-2 x)^2 (3+5 x)^2}{(2+3 x)^6} \, dx=\frac {370}{243\,{\left (3\,x+2\right )}^2}-\frac {100}{243\,\left (3\,x+2\right )}-\frac {503}{243\,{\left (3\,x+2\right )}^3}+\frac {259}{486\,{\left (3\,x+2\right )}^4}-\frac {49}{1215\,{\left (3\,x+2\right )}^5} \]
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